What is the answer to (x^2+x-6)/(x+1)=0 ?

The answer to (x^2+x-6)/(x+1)=0 is x=2,x=-3

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(x^2+x-6)/(x+1)=0

\frac{x ^{2} + x - 6}{x + 1} = 0

x = 2, x = - 3

Solution steps

\frac{x ^{2} + x - 6}{x + 1} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} + x - 6 = 0

Solve

x^{2} + x - 6 = 0 : x = 2, x = - 3

x = 2, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = - 1

Combine undefined points with solutions:

x = 2, x = - 3

\frac{8}{5} = \frac{6}{x}

\frac{1}{x} = 2 x + 1

\frac{1}{3} + \frac{3}{p} = 1

\frac{( m ^{6} + ( - 2 ) )}{1 + m} = 0

\frac{1 - 2 x}{x + 1} = 1 + 2 x

What is the answer to (x^2+x-6)/(x+1)=0 ?
The answer to (x^2+x-6)/(x+1)=0 is x=2,x=-3
Solve for x: (x^2+x-6)/(x+1)=0
The solution is x=2,x=-3