What is factor 27d^6+8g^{12} ?

The solution to factor 27d^6+8g^{12} is (3d^2+2g^4)(9d^4-6d^2g^4+4g^8)

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factor 27d^6+8g^{12}

factor

27 d^{6} + 8 g^{12}

(3 d^{2} + 2 g^{4}) (9 d^{4} - 6 d^{2} g^{4} + 4 g^{8})

Solution steps

27 d^{6} + 8 g^{12}

Apply exponent rules

= (3 d^{2})^{3} + (2 g^{4})^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(3 d^{2})^{3} + (2 g^{4})^{3} = (3 d^{2} + 2 g^{4}) ((3 d^{2})^{2} - 3 d^{2} \cdot 2 g^{4} + (2 g^{4})^{2})

= (3 d^{2} + 2 g^{4}) ((3 d^{2})^{2} - 3 d^{2} \cdot 2 g^{4} + (2 g^{4})^{2})

Simplify

(3 d^{2})^{2} - 3 d^{2} \cdot 2 g^{4} + (2 g^{4})^{2} : 9 d^{4} - 6 d^{2} g^{4} + 4 g^{8}

= (3 d^{2} + 2 g^{4}) (9 d^{4} - 6 d^{2} g^{4} + 4 g^{8})

2 (x - 5)^{2} = 90

36 + 16

0.8 y + 30 > - 24

\frac{1}{7 !}

- 3 + \frac{x}{3} = - 5

What is factor 27d^6+8g^{12} ?
The solution to factor 27d^6+8g^{12} is (3d^2+2g^4)(9d^4-6d^2g^4+4g^8)