What is the answer to (3x+1)/(9x^2+6x+26)=0 ?

The answer to (3x+1)/(9x^2+6x+26)=0 is x=-1/3

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(3x+1)/(9x^2+6x+26)=0

\frac{3 x + 1}{9 x ^{2} + 6 x + 26} = 0

x = - \frac{1}{3}

Decimal Notation

x = - 0.33333 \dots

Solution steps

\frac{3 x + 1}{9 x ^{2} + 6 x + 26} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

3 x + 1 = 0

Move

1

to the right side

3 x = - 1

Divide both sides by

3

x = - \frac{1}{3}

6050 = 11 0^{2} \frac{1}{x}

\frac{3}{x + 1} = \frac{x}{x - 1}

a + \frac{1}{a} = 10

\frac{2 x - 4}{x - 2} = - 7

\frac{2}{10} = \frac{4}{a - 3}

What is the answer to (3x+1)/(9x^2+6x+26)=0 ?
The answer to (3x+1)/(9x^2+6x+26)=0 is x=-1/3
Solve for x: (3x+1)/(9x^2+6x+26)=0
The solution is x=-1/3