What is the answer to 1=(14x^2)/(x^4+49) ?

The answer to 1=(14x^2)/(x^4+49) is x=sqrt(7),x=-sqrt(7)

Solve for x: 1=(14x^2)/(x^4+49)

The solution is x=sqrt(7),x=-sqrt(7)

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1 = \frac{14 x ^{2}}{x ^{4} + 49}

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

1 = \frac{14 x ^{2}}{x ^{4} + 49}

Multiply both sides by

x^{4} + 49

x^{4} + 49 = 14 x^{2}

Solve

x^{4} + 49 = 14 x^{2} : x = 7, x = - 7

x = 7, x = - 7

B (y) = c y^{- 8}

x - \frac{15}{x} = 2

x = \frac{24}{x} + \frac{1}{5}

\frac{x}{2} = \frac{4}{x + 9 x ^{3}}

x + \frac{3}{x} = 5

What is the answer to 1=(14x^2)/(x^4+49) ?
The answer to 1=(14x^2)/(x^4+49) is x=sqrt(7),x=-sqrt(7)
Solve for x: 1=(14x^2)/(x^4+49)
The solution is x=sqrt(7),x=-sqrt(7)