What is the answer to (x+1}{3x}-1=\frac{1-x)/2 ?

The answer to (x+1}{3x}-1=\frac{1-x)/2 is x= 1/3 ,x=2

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(x+1}{3x}-1=\frac{1-x)/2

\frac{x + 1}{3 x} - 1 = \frac{1 - x}{2}

x = \frac{1}{3}, x = 2

Decimal Notation

x = 0.33333 \dots, x = 2

Solution steps

\frac{x + 1}{3 x} - 1 = \frac{1 - x}{2}

Multiply by LCM

2 (x + 1) - 6 x = 3 x (- x + 1)

Solve

2 (x + 1) - 6 x = 3 x (- x + 1) : x = \frac{1}{3}, x = 2

x = \frac{1}{3}, x = 2

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{1}{3}, x = 2

\frac{36}{x} - x = 0

\frac{x}{x - 3} = \frac{5}{3}

3 x + \frac{2}{x} = - 7

\frac{3}{\frac{1}{x}} = 1

\frac{4}{0.6901 \cdot x} = 2

What is the answer to (x+1}{3x}-1=\frac{1-x)/2 ?
The answer to (x+1}{3x}-1=\frac{1-x)/2 is x= 1/3 ,x=2
Solve for x: (x+1}{3x}-1=\frac{1-x)/2
The solution is x= 1/3 ,x=2