What is the answer to 7x^{-2}-33x^{-1}+20=0 ?

The answer to 7x^{-2}-33x^{-1}+20=0 is x= 7/5 ,x= 1/4

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7x^{-2}-33x^{-1}+20=0

7 x^{- 2} - 33 x^{- 1} + 20 = 0

x = \frac{7}{5}, x = \frac{1}{4}

Decimal Notation

x = 1.4, x = 0.25

Solution steps

7 x^{- 2} - 33 x^{- 1} + 20 = 0

Refine

\frac{7}{x ^{2}} - \frac{33}{x} + 20 = 0

Multiply by LCM

7 - 33 x + 20 x^{2} = 0

Solve

7 - 33 x + 20 x^{2} = 0 : x = \frac{7}{5}, x = \frac{1}{4}

x = \frac{7}{5}, x = \frac{1}{4}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{7}{5}, x = \frac{1}{4}

\frac{- 0.87 x}{x - 7} = 0.29

\frac{10}{7 y - 14} = - 4

\frac{7}{4} = \frac{5}{y} - 2

\frac{8}{x + 4} = \frac{6}{x - 4}

\frac{4 x - 1}{x} = 3 x

What is the answer to 7x^{-2}-33x^{-1}+20=0 ?
The answer to 7x^{-2}-33x^{-1}+20=0 is x= 7/5 ,x= 1/4
Solve for x: 7x^{-2}-33x^{-1}+20=0
The solution is x= 7/5 ,x= 1/4