What is the answer to 2/n+3(2-4)^2=16 ?

The answer to 2/n+3(2-4)^2=16 is n= 1/2

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2/n+3(2-4)^2=16

\frac{2}{n} + 3 (2 - 4)^{2} = 16

n = \frac{1}{2}

Decimal Notation

n = 0.5

Solution steps

\frac{2}{n} + 3 (2 - 4)^{2} = 16

Move

3 (2 - 4)^{2}

to the right side

\frac{2}{n} = 4

Multiply both sides by

n

2 = 4 n

Switch sides

4 n = 2

Divide both sides by

4

n = \frac{1}{2}

Verify Solutions

Find undefined (singularity) points:

n = 0

Combine undefined points with solutions:

n = \frac{1}{2}

a, c = \frac{2 ab}{a + b}

2 x - \frac{3}{x + 2} = x

3 x^{- 2} - 19 x^{- 1} + 20 = 0

4 = x + \frac{1}{x}

\frac{3 x - 6}{4 x + 3} = \frac{3}{5}