What is the answer to (2x^3-32x)/(x-4)=20x ?

The answer to (2x^3-32x)/(x-4)=20x is x=0,x=6

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(2x^3-32x)/(x-4)=20x

\frac{2 x ^{3} - 32 x}{x - 4} = 20 x

x = 0, x = 6

Solution steps

\frac{2 x ^{3} - 32 x}{x - 4} = 20 x

Simplify

\frac{2 x ^{3} - 32 x}{x - 4} : 2 x (x + 4)

2 x (x + 4) = 20 x

Solve

2 x (x + 4) = 20 x : x = 0, x = 6

x = 0, x = 6

Verify Solutions

Find undefined (singularity) points:

x = 4

Combine undefined points with solutions:

x = 0, x = 6

\frac{1}{x - 2} = \frac{2}{3 x + 2}

3 = \frac{x}{x - 1}

\frac{2 x}{x + 4} = 9 - \frac{8}{x + 4}

k, y = \frac{1}{k}

\frac{3 x - 2}{x - 5} = (x + 5)

What is the answer to (2x^3-32x)/(x-4)=20x ?
The answer to (2x^3-32x)/(x-4)=20x is x=0,x=6
Solve for x: (2x^3-32x)/(x-4)=20x
The solution is x=0,x=6