What is the answer to (2x)/5+4/(3x)=0 ?

The answer to (2x)/5+4/(3x)=0 is x=sqrt(10/3)i,x=-sqrt(10/3)i

Solve for x: (2x)/5+4/(3x)=0

The solution is x=sqrt(10/3)i,x=-sqrt(10/3)i

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\frac{2 x}{5} + \frac{4}{3 x} = 0

x = \frac{10}{3} i, x = - \frac{10}{3} i

Solution steps

\frac{2 x}{5} + \frac{4}{3 x} = 0

Multiply by LCM

6 x^{2} + 20 = 0

Solve

6 x^{2} + 20 = 0 : x = \frac{10}{3} i, x = - \frac{10}{3} i

x = \frac{10}{3} i, x = - \frac{10}{3} i

\frac{( c + 1 )}{2 c - 2} = \frac{1}{2}

q, t = - \frac{1}{q} rs

\frac{x + 5}{x + 3} = \frac{4}{x}

\frac{1}{x - 1} + \frac{1}{3} = 4

\frac{20}{9} = \frac{5}{x}

What is the answer to (2x)/5+4/(3x)=0 ?
The answer to (2x)/5+4/(3x)=0 is x=sqrt(10/3)i,x=-sqrt(10/3)i
Solve for x: (2x)/5+4/(3x)=0
The solution is x=sqrt(10/3)i,x=-sqrt(10/3)i