What is the answer to 80=(x^2+300x)/(2x+300) ?

The answer to 80=(x^2+300x)/(2x+300) is x=100,x=-240

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80=(x^2+300x)/(2x+300)

80 = \frac{x ^{2} + 300 x}{2 x + 300}

x = 100, x = - 240

Solution steps

80 = \frac{x ^{2} + 300 x}{2 x + 300}

Multiply both sides by

2 x + 300

80 (2 x + 300) = x^{2} + 300 x

Solve

80 (2 x + 300) = x^{2} + 300 x : x = 100, x = - 240

x = 100, x = - 240

Verify Solutions

Find undefined (singularity) points:

x = - 150

Combine undefined points with solutions:

x = 100, x = - 240

x, y = \frac{1}{4 x}

\frac{4}{x - 1} - \frac{3 - x}{2} = 2

6817 = \frac{( x + 2 )}{( x + 4.47 )}

\frac{x - 10}{x + 1} = 0

2 x = \frac{1}{x} + 1

What is the answer to 80=(x^2+300x)/(2x+300) ?
The answer to 80=(x^2+300x)/(2x+300) is x=100,x=-240
Solve for x: 80=(x^2+300x)/(2x+300)
The solution is x=100,x=-240