What are the solutions to the equation x^2-42=-x ?

The solutions to the equation x^2-42=-x are x=6,x=-7

Find the zeros of x^2-42=-x

The zeros of x^2-42=-x are x=6,x=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 42 = - x

x = 6, x = - 7

Solution steps

x^{2} - 42 = - x

Move

x

to the left side

x^{2} - 42 + x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 42 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 42) = 13

x_{1, 2} = \frac{- 1 \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 13}{2 \cdot 1}, x_{2} = \frac{- 1 - 13}{2 \cdot 1}

x = \frac{- 1 + 13}{2 \cdot 1} : 6

x = \frac{- 1 - 13}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 6, x = - 7

\frac{4}{x + 2} < 0

\frac{1}{4} - \frac{7}{2}

\frac{5}{2} x + 1 < \frac{1}{5} - 2 x

4 x + 9 > - 11

\frac{x ^{- 1} + y ^{- 1}}{( x y ) ^{- 1}}

What are the solutions to the equation x^2-42=-x ?
The solutions to the equation x^2-42=-x are x=6,x=-7
Find the zeros of x^2-42=-x
The zeros of x^2-42=-x are x=6,x=-7