What is the answer to -4=r^{-4} ?

The answer to -4=r^{-4} is r= 1/2+1/2 i,r=-1/2-1/2 i,r= 1/2-1/2 i,r=-1/2+1/2 i

Solve for r: -4=r^{-4}

The solution is r= 1/2+1/2 i,r=-1/2-1/2 i,r= 1/2-1/2 i,r=-1/2+1/2 i

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- 4 = r^{- 4}

r = \frac{1}{2} + \frac{1}{2} i, r = - \frac{1}{2} - \frac{1}{2} i, r = \frac{1}{2} - \frac{1}{2} i, r = - \frac{1}{2} + \frac{1}{2} i

Solution steps

- 4 = r^{- 4}

Refine

- 4 = \frac{1}{r ^{4}}

Multiply both sides by

r^{4}

- 4 r^{4} = 1

Solve

- 4 r^{4} = 1 : r = \frac{1}{2} + \frac{1}{2} i, r = - \frac{1}{2} - \frac{1}{2} i, r = \frac{1}{2} - \frac{1}{2} i, r = - \frac{1}{2} + \frac{1}{2} i

r = \frac{1}{2} + \frac{1}{2} i, r = - \frac{1}{2} - \frac{1}{2} i, r = \frac{1}{2} - \frac{1}{2} i, r = - \frac{1}{2} + \frac{1}{2} i

\frac{2 x - 1}{x + 3} = x + 1

\frac{X - 70}{X} = \frac{7}{20}

\frac{x - 5}{( x - 1 ) ^{3}} = 0

x^{- 2} - 6 x^{- 1} + 8 = 0

\frac{11}{x - 5} = - \frac{3}{7 + 2 x}

What is the answer to -4=r^{-4} ?
The answer to -4=r^{-4} is r= 1/2+1/2 i,r=-1/2-1/2 i,r= 1/2-1/2 i,r=-1/2+1/2 i
Solve for r: -4=r^{-4}
The solution is r= 1/2+1/2 i,r=-1/2-1/2 i,r= 1/2-1/2 i,r=-1/2+1/2 i