What is the answer to ((x-3)^2)/(x^2-5x)=1 ?

The answer to ((x-3)^2)/(x^2-5x)=1 is x=9

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((x-3)^2)/(x^2-5x)=1

\frac{( x - 3 ) ^{2}}{x ^{2} - 5 x} = 1

x = 9

Solution steps

\frac{( x - 3 ) ^{2}}{x ^{2} - 5 x} = 1

Multiply both sides by

x^{2} - 5 x

(x - 3)^{2} = x^{2} - 5 x

Expand

(x - 3)^{2} : x^{2} - 6 x + 9

x^{2} - 6 x + 9 = x^{2} - 5 x

Move

9

to the right side

x^{2} - 6 x = x^{2} - 5 x - 9

Subtract

x^{2} - 5 x

from both sides

x^{2} - 6 x - (x^{2} - 5 x) = x^{2} - 5 x - 9 - (x^{2} - 5 x)

Simplify

- x = - 9

Divide both sides by

- 1

x = 9

Verify Solutions

Find undefined (singularity) points:

x = 5, x = 0

Combine undefined points with solutions:

x = 9

\frac{x}{x - 2} + \frac{4}{x - 2} = 10

y, x = \frac{1}{y - 2}

\frac{x - 7}{3 x} + 1 = \frac{x + 5}{x}

\frac{45}{30} = \frac{36}{x}

\frac{x}{- 7 x + 2} = - 2 x - 33

What is the answer to ((x-3)^2)/(x^2-5x)=1 ?
The answer to ((x-3)^2)/(x^2-5x)=1 is x=9
Solve for x: ((x-3)^2)/(x^2-5x)=1
The solution is x=9