What is the answer to -(16x)/((x^2-4)^2)=0 ?

The answer to -(16x)/((x^2-4)^2)=0 is x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-(16x)/((x^2-4)^2)=0

- \frac{16 x}{( x ^{2} - 4 ) ^{2}} = 0

x = 0

Solution steps

- \frac{16 x}{( x ^{2} - 4 ) ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

16 x = 0

Divide both sides by

16

x = 0

Verify Solutions

Find undefined (singularity) points:

x = 2, x = - 2

Combine undefined points with solutions:

x = 0

\frac{x + 5}{x} = \frac{7}{3}

(a + \frac{1}{a})^{2} = 3

\frac{( x ^{4} - 1 )}{( x ^{3} )} = 0

\frac{( N + 1 ) !}{( N - 1 ) !} = 56

\frac{9}{1} = \frac{100}{x}

What is the answer to -(16x)/((x^2-4)^2)=0 ?
The answer to -(16x)/((x^2-4)^2)=0 is x=0
Solve for x: -(16x)/((x^2-4)^2)=0
The solution is x=0