What is the answer to i=(pn)/(pn+1) ?

The answer to i=(pn)/(pn+1) is p=-i/(n(i-1));\quad n(i-1)\ne 0

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i=(pn)/(pn+1)

i = \frac{p n}{p n + 1}

p = - \frac{i}{n ( i - 1 )}; n (i - 1) \neq = 0

Solution steps

i = \frac{p n}{p n + 1}

Multiply both sides by

p n + 1

i (p n + 1) = n p

Expand

i (p n + 1) : in p + i

in p + i = n p

Move

i

to the right side

in p = n p - i

Move

n p

to the left side

in p - n p = - i

Factor

in p - n p : n p (i - 1)

n p (i - 1) = - i

Divide both sides by

n (i - 1); n (i - 1) \neq = 0

p = - \frac{i}{n ( i - 1 )}; n (i - 1) \neq = 0

9.70802 = \frac{11.9}{t}

- 1000 \cdot (\frac{0.8}{x}) = - 9

x, u = \frac{k}{x}

1 + \frac{x}{x - 5} = \frac{1}{x - 5}

\frac{1}{2 x + 6} - \frac{x}{x + 3} = 0

What is the answer to i=(pn)/(pn+1) ?
The answer to i=(pn)/(pn+1) is p=-i/(n(i-1));\quad n(i-1)\ne 0