What are the solutions to the equation (x-2)^2=1 ?

The solutions to the equation (x-2)^2=1 are x=3,x=1

Find the zeros of (x-2)^2=1

The zeros of (x-2)^2=1 are x=3,x=1

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(x - 2)^{2} = 1

x = 3, x = 1

Solution steps

(x - 2)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 1 : x = 3

Solve

x - 2 = - 1 : x = 1

The solutions to the quadratic equation are:

x = 3, x = 1

- 6 = \frac{x}{8} + 4

- 3.24

- 5 (2 x - 4) + 2 \geq - 13

- 1 \leq 9 - 2 \frac{x}{5} < 4

20 s + 4 = 13 s - 10

What are the solutions to the equation (x-2)^2=1 ?
The solutions to the equation (x-2)^2=1 are x=3,x=1
Find the zeros of (x-2)^2=1
The zeros of (x-2)^2=1 are x=3,x=1