What is the answer to -2((y^2-1)/y)y+y^2=1 ?

The answer to -2((y^2-1)/y)y+y^2=1 is y=1,y=-1

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-2((y^2-1)/y)y+y^2=1

- 2 (\frac{y ^{2} - 1}{y}) y + y^{2} = 1

y = 1, y = - 1

Solution steps

- 2 (\frac{y ^{2} - 1}{y}) y + y^{2} = 1

Simplify

- 2 (\frac{y ^{2} - 1}{y}) y : - 2 (y^{2} - 1)

- 2 (y^{2} - 1) + y^{2} = 1

Solve

- 2 (y^{2} - 1) + y^{2} = 1 : y = 1, y = - 1

y = 1, y = - 1

Verify Solutions

Find undefined (singularity) points:

y = 0

Combine undefined points with solutions:

y = 1, y = - 1

\frac{6}{2 x} = \frac{24}{32}

x^{- 2} - 3 x^{- 1} + \frac{1}{5} = 0

u - 12 (u)^{- 1} - 1 = 0

- \frac{8}{( x - 2 ) ^{2}} = - 2

\frac{a}{a - 1} = - \frac{4}{3}

What is the answer to -2((y^2-1)/y)y+y^2=1 ?
The answer to -2((y^2-1)/y)y+y^2=1 is y=1,y=-1
Solve for y: -2((y^2-1)/y)y+y^2=1
The solution is y=1,y=-1