What is the answer to 2x-2+3/(x+2)=0 ?

The answer to 2x-2+3/(x+2)=0 is x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2

Solve for x: 2x-2+3/(x+2)=0

The solution is x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2

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2 x - 2 + \frac{3}{x + 2} = 0

x = \frac{- 1 + 3}{2}, x = - \frac{1 + 3}{2}

Decimal Notation

x = 0.36602 \dots, x = - 1.36602 \dots

Solution steps

2 x - 2 + \frac{3}{x + 2} = 0

Multiply both sides by

x + 2

2 x (x + 2) - 2 (x + 2) + 3 = 0

Solve

2 x (x + 2) - 2 (x + 2) + 3 = 0 : x = \frac{- 1 + 3}{2}, x = - \frac{1 + 3}{2}

x = \frac{- 1 + 3}{2}, x = - \frac{1 + 3}{2}

Verify Solutions

Find undefined (singularity) points:

x = - 2

Combine undefined points with solutions:

x = \frac{- 1 + 3}{2}, x = - \frac{1 + 3}{2}

\frac{3 x + 7}{x + 2} + x = 3

ab = \frac{m}{x + 1}

0 = \frac{5}{x ^{2} + 1}

\frac{1}{2 x + 13 - 1.5 x} = 3 x + 6 - 9

21 x - \frac{4}{x} = 8

What is the answer to 2x-2+3/(x+2)=0 ?
The answer to 2x-2+3/(x+2)=0 is x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2
Solve for x: 2x-2+3/(x+2)=0
The solution is x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2