What is the answer to solvefor a,n= b/a+3 ?

The answer to solvefor a,n= b/a+3 is a= b/(n-3);\quad n\ne 3

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solvefor a,n= b/a+3

solve for

a, n = \frac{b}{a} + 3

a = \frac{b}{n - 3}; n \neq = 3

Solution steps

n = \frac{b}{a} + 3

Move

3

to the left side

n - 3 = \frac{b}{a}

Multiply both sides by

a

na - 3 a = b

Factor

na - 3 a : a (n - 3)

a (n - 3) = b

Divide both sides by

n - 3; n \neq = 3

a = \frac{b}{n - 3}; n \neq = 3

\frac{x ^{2} - 1}{x - 1} = 3

\frac{12}{x} = \frac{12}{16}

r, S = \frac{r}{1 - r}

\frac{4}{1 + x ^{2}} = 1

2 x^{- 3} = \frac{2}{x ^{3}}

What is the answer to solvefor a,n= b/a+3 ?
The answer to solvefor a,n= b/a+3 is a= b/(n-3);\quad n\ne 3