What is the answer to 1/x+3/(x^2)=-1 ?

The answer to 1/x+3/(x^2)=-1 is x=-1/2-i(sqrt(11))/2 ,x=-1/2+i(sqrt(11))/2

Solve for x: 1/x+3/(x^2)=-1

The solution is x=-1/2-i(sqrt(11))/2 ,x=-1/2+i(sqrt(11))/2

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\frac{1}{x} + \frac{3}{x ^{2}} = - 1

x = - \frac{1}{2} - i \frac{11}{2}, x = - \frac{1}{2} + i \frac{11}{2}

Solution steps

\frac{1}{x} + \frac{3}{x ^{2}} = - 1

Multiply by LCM

x + 3 = - x^{2}

Solve

x + 3 = - x^{2} : x = - \frac{1}{2} - i \frac{11}{2}, x = - \frac{1}{2} + i \frac{11}{2}

x = - \frac{1}{2} - i \frac{11}{2}, x = - \frac{1}{2} + i \frac{11}{2}

- \frac{1}{x ^{2}} + 1 = 0

2 x + \frac{1}{x} = \frac{18}{10}

\frac{2}{5} = \frac{3}{y} - 2

x, \frac{- 2}{x + 4} = y

a, \frac{x}{a} + b = c

What is the answer to 1/x+3/(x^2)=-1 ?
The answer to 1/x+3/(x^2)=-1 is x=-1/2-i(sqrt(11))/2 ,x=-1/2+i(sqrt(11))/2
Solve for x: 1/x+3/(x^2)=-1
The solution is x=-1/2-i(sqrt(11))/2 ,x=-1/2+i(sqrt(11))/2