What is the answer to solvefor y,x=(3-y)/(y-1) ?

The answer to solvefor y,x=(3-y)/(y-1) is y=(3+x)/(x+1);\quad x\ne-1

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solvefor y,x=(3-y)/(y-1)

solve for

y, x = \frac{3 - y}{y - 1}

y = \frac{3 + x}{x + 1}; x \neq = - 1

Solution steps

x = \frac{3 - y}{y - 1}

Multiply both sides by

y - 1

x (y - 1) = 3 - y

Expand

x (y - 1) : y x - x

y x - x = 3 - y

Move

x

to the right side

y x = 3 - y + x

Move

y

to the left side

y x + y = 3 + x

Factor

y x + y : y (x + 1)

y (x + 1) = 3 + x

Divide both sides by

x + 1; x \neq = - 1

y = \frac{3 + x}{x + 1}; x \neq = - 1

\frac{x ^{3} - x ^{2}}{x + 2} = 0

\frac{8}{x + 3} = \frac{2 x + 10}{6}

\frac{x}{4 x + 5} = 3

\frac{2}{5} = \frac{3}{x}

(x) = 4 x + 720 + \frac{921600}{x}

What is the answer to solvefor y,x=(3-y)/(y-1) ?
The answer to solvefor y,x=(3-y)/(y-1) is y=(3+x)/(x+1);\quad x\ne-1