What is the answer to ((4x+1))/((2x+2))=128 ?

The answer to ((4x+1))/((2x+2))=128 is x=-85/84

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((4x+1))/((2x+2))=128

\frac{( 4 x + 1 )}{( 2 x + 2 )} = 128

x = - \frac{85}{84}

Decimal Notation

x = - 1.01190 \dots

Solution steps

\frac{( 4 x + 1 )}{( 2 x + 2 )} = 128

Simplify

\frac{( 4 x + 1 )}{( 2 x + 2 )} : \frac{4 x + 1}{2 x + 2}

\frac{4 x + 1}{2 x + 2} = 128

Multiply both sides by

2 x + 2

4 x + 1 = 128 (2 x + 2)

Expand

128 (2 x + 2) : 256 x + 256

4 x + 1 = 256 x + 256

Move

1

to the right side

4 x = 256 x + 255

Move

256 x

to the left side

- 252 x = 255

Divide both sides by

- 252

x = - \frac{85}{84}

Verify Solutions

Find undefined (singularity) points:

x = - 1

Combine undefined points with solutions:

x = - \frac{85}{84}

\frac{1}{6 x} = \frac{4}{15}

\frac{A X + B}{X} = \frac{CX}{D}

\frac{750}{x - 750} = 2.083

(x) = \frac{1}{( x - 3 )}

\frac{2}{x} - \frac{5}{x + 2} = 1

What is the answer to ((4x+1))/((2x+2))=128 ?
The answer to ((4x+1))/((2x+2))=128 is x=-85/84
Solve for x: ((4x+1))/((2x+2))=128
The solution is x=-85/84