What is the answer to solvefor x,y= 1/(x-3) ?

The answer to solvefor x,y= 1/(x-3) is x= 1/y+3;\quad y\ne 0

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solvefor x,y= 1/(x-3)

solve for

x, y = \frac{1}{x - 3}

x = \frac{1}{y} + 3; y \neq = 0

Solution steps

y = \frac{1}{x - 3}

Multiply both sides by

x - 3

y (x - 3) = 1

Divide both sides by

y; y \neq = 0

x - 3 = \frac{1}{y}; y \neq = 0

Move

3

to the right side

x = \frac{1}{y} + 3; y \neq = 0

\frac{5}{12} = \frac{5 x - 9}{x}

2.5 = \frac{x}{1 - x}

\frac{4}{3 + x} = 0

(\frac{1}{( t - 2 )}) = \frac{t}{8}

\frac{4}{5} = \frac{x}{x - 2}

What is the answer to solvefor x,y= 1/(x-3) ?
The answer to solvefor x,y= 1/(x-3) is x= 1/y+3;\quad y\ne 0