What are the solutions to the equation 7x^2-33x-10=0 ?

The solutions to the equation 7x^2-33x-10=0 are x=5,x=-2/7

Find the zeros of 7x^2-33x-10=0

The zeros of 7x^2-33x-10=0 are x=5,x=-2/7

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7 x^{2} - 33 x - 10 = 0

x = 5, x = - \frac{2}{7}

Decimal Notation

x = 5, x = - 0.28571 \dots

Solution steps

7 x^{2} - 33 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 33 ) \pm ( - 33 ) ^{2} - 4 \cdot 7 ( - 10 )}{2 \cdot 7}

(- 33)^{2} - 4 \cdot 7 (- 10) = 37

x_{1, 2} = \frac{- ( - 33 ) \pm 37}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 33 ) + 37}{2 \cdot 7}, x_{2} = \frac{- ( - 33 ) - 37}{2 \cdot 7}

x = \frac{- ( - 33 ) + 37}{2 \cdot 7} : 5

x = \frac{- ( - 33 ) - 37}{2 \cdot 7} : - \frac{2}{7}

The solutions to the quadratic equation are:

x = 5, x = - \frac{2}{7}

- 10 n^{2} - 25 n + 20

\frac{32 !}{( 32 - 4 ) ! 4 !}

7 x^{2} - 3 x + 1 = 0

\frac{x - 3}{x + 1} \geq 0

3 n + 4 n = - 14

What are the solutions to the equation 7x^2-33x-10=0 ?
The solutions to the equation 7x^2-33x-10=0 are x=5,x=-2/7
Find the zeros of 7x^2-33x-10=0
The zeros of 7x^2-33x-10=0 are x=5,x=-2/7