What is factor p^4-q^4 ?

The solution to factor p^4-q^4 is (p^2+q^2)(p+q)(p-q)

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factor p^4-q^4

factor

p^{4} - q^{4}

(p^{2} + q^{2}) (p + q) (p - q)

Solution steps

p^{4} - q^{4}

p^{4} = (p^{2})^{2}

q^{4} = (q^{2})^{2}

= (p^{2})^{2} - (q^{2})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(p^{2})^{2} - (q^{2})^{2} = (p^{2} + q^{2}) (p^{2} - q^{2})

= (p^{2} + q^{2}) (p^{2} - q^{2})

Factor

p^{2} - q^{2} : (p + q) (p - q)

= (p^{2} + q^{2}) (p + q) (p - q)

8 x^{2} - 22 x + 5

x (x + 1)^{2} (x - 7) < 0

\frac{\frac{5}{2}}{2}

3 x + 5 = 2 x - 1

6 x (x^{2} + 1)^{2} (2 x + 1) + 2 (x^{2} + 1)^{3}