What are the solutions to the equation 0=X^2+7X+12 ?

The solutions to the equation 0=X^2+7X+12 are X=-3,X=-4

Find the zeros of 0=X^2+7X+12

The zeros of 0=X^2+7X+12 are X=-3,X=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = X^{2} + 7 X + 12

X = - 3, X = - 4

Solution steps

0 = X^{2} + 7 X + 12

Switch sides

X^{2} + 7 X + 12 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 12 = 1

X_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 7 + 1}{2 \cdot 1}, X_{2} = \frac{- 7 - 1}{2 \cdot 1}

X = \frac{- 7 + 1}{2 \cdot 1} : - 3

X = \frac{- 7 - 1}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

X = - 3, X = - 4

12 x^{2} - 40 x - 63 = 0

3 x + 5 = 1

(\frac{3}{5})^{4}

120

(2 a - b) (2 x - 2 y)^{2} - (6 a - 3 b)^{3} (x - y)

What are the solutions to the equation 0=X^2+7X+12 ?
The solutions to the equation 0=X^2+7X+12 are X=-3,X=-4
Find the zeros of 0=X^2+7X+12
The zeros of 0=X^2+7X+12 are X=-3,X=-4