What is the answer to solvefor y,x= 3/(y^2-1) ?

The answer to solvefor y,x= 3/(y^2-1) is y=sqrt(3/x+1),y=-sqrt(3/x+1);\quad x\ne 0

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solvefor y,x= 3/(y^2-1)

solve for

y, x = \frac{3}{y ^{2} - 1}

y = \frac{3}{x} + 1, y = - \frac{3}{x} + 1; x \neq = 0

Solution steps

x = \frac{3}{y ^{2} - 1}

Multiply both sides by

y^{2} - 1

x (y^{2} - 1) = 3

Solve

x (y^{2} - 1) = 3 : y = \frac{3}{x} + 1, y = - \frac{3}{x} + 1; x \neq = 0

y = \frac{3}{x} + 1, y = - \frac{3}{x} + 1; x \neq = 0

- \frac{4}{9} = \frac{x - 7}{x + 6}

a = \frac{1800}{x} + 20

b (x) = \frac{( x ^{2} - 4 )}{( x - 3 )}

3.834057 = \frac{0.75}{x}

\frac{6}{5} = \frac{2}{y}

What is the answer to solvefor y,x= 3/(y^2-1) ?
The answer to solvefor y,x= 3/(y^2-1) is y=sqrt(3/x+1),y=-sqrt(3/x+1);\quad x\ne 0