What are the solutions to the equation 25x^2-90x+82=0 ?

The solutions to the equation 25x^2-90x+82=0 are x= 9/5+i 1/5 ,x= 9/5-i 1/5

Find the zeros of 25x^2-90x+82=0

The zeros of 25x^2-90x+82=0 are x= 9/5+i 1/5 ,x= 9/5-i 1/5

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25 x^{2} - 90 x + 82 = 0

x = \frac{9}{5} + i \frac{1}{5}, x = \frac{9}{5} - i \frac{1}{5}

Solution steps

25 x^{2} - 90 x + 82 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 90 ) \pm ( - 90 ) ^{2} - 4 \cdot 25 \cdot 82}{2 \cdot 25}

Simplify

(- 90)^{2} - 4 \cdot 25 \cdot 82 : 10 i

x_{1, 2} = \frac{- ( - 90 ) \pm 10 i}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 90 ) + 10 i}{2 \cdot 25}, x_{2} = \frac{- ( - 90 ) - 10 i}{2 \cdot 25}

x = \frac{- ( - 90 ) + 10 i}{2 \cdot 25} : \frac{9}{5} + i \frac{1}{5}

x = \frac{- ( - 90 ) - 10 i}{2 \cdot 25} : \frac{9}{5} - i \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{9}{5} + i \frac{1}{5}, x = \frac{9}{5} - i \frac{1}{5}

\frac{1}{- 5}

- \frac{18}{( 3 ( - 1 ) + 1 ) ^{2}}

- 5 + (7 \times 9)

136 = 24 - 8 p

\frac{3 + 4 i}{2 + i}

What are the solutions to the equation 25x^2-90x+82=0 ?
The solutions to the equation 25x^2-90x+82=0 are x= 9/5+i 1/5 ,x= 9/5-i 1/5
Find the zeros of 25x^2-90x+82=0
The zeros of 25x^2-90x+82=0 are x= 9/5+i 1/5 ,x= 9/5-i 1/5