What is the answer to 1/(2x+3)=(2x+3)^{-1} ?

The answer to 1/(2x+3)=(2x+3)^{-1} is x\ne-3/2

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1/(2x+3)=(2x+3)^{-1}

\frac{1}{2 x + 3} = (2 x + 3)^{- 1}

x \neq = - \frac{3}{2}

Solution steps

\frac{1}{2 x + 3} = (2 x + 3)^{- 1}

Refine

\frac{1}{2 x + 3} = \frac{1}{2 x + 3}

Subtract

\frac{1}{2 x + 3}

from both sides

\frac{1}{2 x + 3} - \frac{1}{2 x + 3} = \frac{1}{2 x + 3} - \frac{1}{2 x + 3}

Simplify

0 = 0

Both sides are equal

True for all x

Verify Solutions

Find undefined (singularity) points:

x = - \frac{3}{2}

Since the equation is undefined for:

- \frac{3}{2}

x \neq = - \frac{3}{2}

\frac{1}{x ^{2}} = 10

6 = \frac{3}{2 x - 2.5}

\frac{5}{x + 1} - \frac{2}{x + 3} = 2

\frac{0.392}{x} = 0.7

x + \frac{5}{( x - 1 )} = 2

What is the answer to 1/(2x+3)=(2x+3)^{-1} ?
The answer to 1/(2x+3)=(2x+3)^{-1} is x\ne-3/2
Solve for x: 1/(2x+3)=(2x+3)^{-1}
The solution is x\ne-3/2