What is the answer to x^{-1}(x^2+x+1)= 13/3 ?

The answer to x^{-1}(x^2+x+1)= 13/3 is x=3,x= 1/3

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x^{-1}(x^2+x+1)= 13/3

x^{- 1} (x^{2} + x + 1) = \frac{13}{3}

x = 3, x = \frac{1}{3}

Decimal Notation

x = 3, x = 0.33333 \dots

Solution steps

x^{- 1} (x^{2} + x + 1) = \frac{13}{3}

Refine

\frac{x ^{2} + x + 1}{x} = \frac{13}{3}

Cross multiply

(x^{2} + x + 1) \cdot 3 = x \cdot 13

Solve

(x^{2} + x + 1) \cdot 3 = x \cdot 13 : x = 3, x = \frac{1}{3}

x = 3, x = \frac{1}{3}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 3, x = \frac{1}{3}

\frac{4}{7} = \frac{5}{t + 1}

5 = (3 a - 2)^{- 1}

2 + \frac{1}{x + 4} = 0

\frac{12}{3} = \frac{36}{x}

997773 = \frac{99122}{x}

What is the answer to x^{-1}(x^2+x+1)= 13/3 ?
The answer to x^{-1}(x^2+x+1)= 13/3 is x=3,x= 1/3
Solve for x: x^{-1}(x^2+x+1)= 13/3
The solution is x=3,x= 1/3