What is the answer to 0=(2x^2-9)/(3-x) ?

The answer to 0=(2x^2-9)/(3-x) is x= 3/(sqrt(2)),x=-3/(sqrt(2))

Solve for x: 0=(2x^2-9)/(3-x)

The solution is x= 3/(sqrt(2)),x=-3/(sqrt(2))

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0 = \frac{2 x ^{2} - 9}{3 - x}

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 2.12132 \dots, x = - 2.12132 \dots

Solution steps

0 = \frac{2 x ^{2} - 9}{3 - x}

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

0 = 2 x^{2} - 9

Solve

0 = 2 x^{2} - 9 : x = \frac{3}{2}, x = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

Verify Solutions

Find undefined (singularity) points:

x = 3

Combine undefined points with solutions:

x = \frac{3}{2}, x = - \frac{3}{2}

\frac{4}{x - 2} = 1 + \frac{6}{x + 2}

2.75 = \frac{108.3}{x}

\frac{6}{x - 3} = \frac{- 1}{2}

x - 1 - \frac{1}{x - 1} = 0

\frac{x + 3}{x} = 2

What is the answer to 0=(2x^2-9)/(3-x) ?
The answer to 0=(2x^2-9)/(3-x) is x= 3/(sqrt(2)),x=-3/(sqrt(2))
Solve for x: 0=(2x^2-9)/(3-x)
The solution is x= 3/(sqrt(2)),x=-3/(sqrt(2))