What is the answer to 3/(2(x-1)^2)=sqrt(3) ?

The answer to 3/(2(x-1)^2)=sqrt(3) is x=sqrt((\sqrt{3))/2}+1,x=-sqrt((\sqrt{3))/2}+1

Solve for x: 3/(2(x-1)^2)=sqrt(3)

The solution is x=sqrt((\sqrt{3))/2}+1,x=-sqrt((\sqrt{3))/2}+1

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\frac{3}{2 ( x - 1 ) ^{2}} = 3

x = \frac{3}{2} + 1, x = - \frac{3}{2} + 1

Decimal Notation

x = 1.93060 \dots, x = 0.06939 \dots

Solution steps

\frac{3}{2 ( x - 1 ) ^{2}} = 3

Multiply both sides by

2 (x - 1)^{2}

3 = 3 \cdot 2 (x - 1)^{2}

Solve

3 = 3 \cdot 2 (x - 1)^{2} : x = \frac{3}{2} + 1, x = - \frac{3}{2} + 1

x = \frac{3}{2} + 1, x = - \frac{3}{2} + 1

Verify Solutions

Find undefined (singularity) points:

x = 1

Combine undefined points with solutions:

x = \frac{3}{2} + 1, x = - \frac{3}{2} + 1

- 7 = - \frac{3}{x + 3}

9 = \frac{( 2 x ) ^{2}}{( 1 - x ) ( 1 - x )}

\frac{84}{r} = - 7

400 = \frac{5}{2 \times 1000 x ( 4 )}

\frac{2}{x} - \frac{5}{2 x - 1} = 0

What is the answer to 3/(2(x-1)^2)=sqrt(3) ?
The answer to 3/(2(x-1)^2)=sqrt(3) is x=sqrt((\sqrt{3))/2}+1,x=-sqrt((\sqrt{3))/2}+1
Solve for x: 3/(2(x-1)^2)=sqrt(3)
The solution is x=sqrt((\sqrt{3))/2}+1,x=-sqrt((\sqrt{3))/2}+1