What are the solutions to the equation x^2+16x-145=10x-7 ?

The solutions to the equation x^2+16x-145=10x-7 are x=-3+7sqrt(3),x=-3-7sqrt(3)

Find the zeros of x^2+16x-145=10x-7

The zeros of x^2+16x-145=10x-7 are x=-3+7sqrt(3),x=-3-7sqrt(3)

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x^{2} + 16 x - 145 = 10 x - 7

x = - 3 + 73, x = - 3 - 73

Solution steps

x^{2} + 16 x - 145 = 10 x - 7

Move

7

to the left side

x^{2} + 16 x - 138 = 10 x

Move

10 x

to the left side

x^{2} + 6 x - 138 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 138 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 138) = 143

x_{1, 2} = \frac{- 6 \pm 14 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 14 3}{2 \cdot 1}, x_{2} = \frac{- 6 - 14 3}{2 \cdot 1}

x = \frac{- 6 + 14 3}{2 \cdot 1} : - 3 + 73

x = \frac{- 6 - 14 3}{2 \cdot 1} : - 3 - 73

The solutions to the quadratic equation are:

x = - 3 + 73, x = - 3 - 73

3.4 = - 13.6 + (- 3.4 c) + 1.7 c

x^{2} + 21 < 10 x

x^{2} = 7 x + 3

5 y - [2 (y + 1) + 2] = 7 y

52 - 6 (7 w - 3) \geq 8 (4 - 3 w)

What are the solutions to the equation x^2+16x-145=10x-7 ?
The solutions to the equation x^2+16x-145=10x-7 are x=-3+7sqrt(3),x=-3-7sqrt(3)
Find the zeros of x^2+16x-145=10x-7
The zeros of x^2+16x-145=10x-7 are x=-3+7sqrt(3),x=-3-7sqrt(3)