What is the answer to k=((l^2)/m)+1 ?

The answer to k=((l^2)/m)+1 is m=(l^2)/(k-1);\quad k\ne 1

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k=((l^2)/m)+1

k = (\frac{l ^{2}}{m}) + 1

m = \frac{l ^{2}}{k - 1}; k \neq = 1

Solution steps

k = (\frac{l ^{2}}{m}) + 1

Move

1

to the left side

k - 1 = \frac{l ^{2}}{m}

Multiply both sides by

m

km - m = l^{2}

Factor

km - m : m (k - 1)

m (k - 1) = l^{2}

Divide both sides by

k - 1; k \neq = 1

m = \frac{l ^{2}}{k - 1}; k \neq = 1

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\frac{3}{x - 3} = - 1

1.3 + \frac{0.5633}{1.3 + h} = 1.5

1 = 2 x + \frac{300000}{x}

\frac{4 x + 5}{x} = \frac{3 x + 5}{4}

What is the answer to k=((l^2)/m)+1 ?
The answer to k=((l^2)/m)+1 is m=(l^2)/(k-1);\quad k\ne 1