What is the answer to y+3+1/(y+3)=1 ?

The answer to y+3+1/(y+3)=1 is y=-5/2+i(sqrt(3))/2 ,y=-5/2-i(sqrt(3))/2

Solve for y: y+3+1/(y+3)=1

The solution is y=-5/2+i(sqrt(3))/2 ,y=-5/2-i(sqrt(3))/2

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y + 3 + \frac{1}{y + 3} = 1

y = - \frac{5}{2} + i \frac{3}{2}, y = - \frac{5}{2} - i \frac{3}{2}

Solution steps

y + 3 + \frac{1}{y + 3} = 1

Move

3

to the right side

y + \frac{1}{y + 3} = - 2

Multiply both sides by

y + 3

y (y + 3) + 1 = - 2 (y + 3)

Solve

y (y + 3) + 1 = - 2 (y + 3) : y = - \frac{5}{2} + i \frac{3}{2}, y = - \frac{5}{2} - i \frac{3}{2}

y = - \frac{5}{2} + i \frac{3}{2}, y = - \frac{5}{2} - i \frac{3}{2}

x^{- 2} - 8 x^{- 1} + 15 = 0

\frac{4}{5 x + 8} = - 24

\frac{5}{3 t} = 3 - (\frac{6}{15 t})

\frac{1}{x} + \frac{1}{3 x} = 12

x^{- 2} + 9 x^{- 1} - 10 = 0

What is the answer to y+3+1/(y+3)=1 ?
The answer to y+3+1/(y+3)=1 is y=-5/2+i(sqrt(3))/2 ,y=-5/2-i(sqrt(3))/2
Solve for y: y+3+1/(y+3)=1
The solution is y=-5/2+i(sqrt(3))/2 ,y=-5/2-i(sqrt(3))/2