What is the answer to 441x^{-4}-58x^{-2}+1=0 ?

The answer to 441x^{-4}-58x^{-2}+1=0 is x=7,x=-7,x=3,x=-3

Solve for x: 441x^{-4}-58x^{-2}+1=0

The solution is x=7,x=-7,x=3,x=-3

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441 x^{- 4} - 58 x^{- 2} + 1 = 0

x = 7, x = - 7, x = 3, x = - 3

Solution steps

441 x^{- 4} - 58 x^{- 2} + 1 = 0

Refine

\frac{441}{x ^{4}} - \frac{58}{x ^{2}} + 1 = 0

Multiply by LCM

441 - 58 x^{2} + x^{4} = 0

Solve

441 - 58 x^{2} + x^{4} = 0 : x = 7, x = - 7, x = 3, x = - 3

x = 7, x = - 7, x = 3, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 7, x = - 7, x = 3, x = - 3

\frac{1 + y ^{3} + 2 y ^{2}}{y ^{2}} = 0

0.876 = \frac{230}{v}

t, P = \frac{t}{t}

2 + \frac{4}{y} = \frac{7}{12 y}

\frac{6}{7} = \frac{4}{m}

What is the answer to 441x^{-4}-58x^{-2}+1=0 ?
The answer to 441x^{-4}-58x^{-2}+1=0 is x=7,x=-7,x=3,x=-3
Solve for x: 441x^{-4}-58x^{-2}+1=0
The solution is x=7,x=-7,x=3,x=-3