What is the answer to (x^2-3x-4)/(x+2)=0 ?

The answer to (x^2-3x-4)/(x+2)=0 is x=4,x=-1

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(x^2-3x-4)/(x+2)=0

\frac{x ^{2} - 3 x - 4}{x + 2} = 0

x = 4, x = - 1

Solution steps

\frac{x ^{2} - 3 x - 4}{x + 2} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} - 3 x - 4 = 0

Solve

x^{2} - 3 x - 4 = 0 : x = 4, x = - 1

x = 4, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = - 2

Combine undefined points with solutions:

x = 4, x = - 1

r, M = \frac{N}{r}

\frac{150000 - 1000 P}{1000 P} = 0.4

(20) = (\frac{32.76 x}{32.76 + x})

s L + 2 = \frac{4}{s}

- 2 - \frac{6}{x} = - \frac{7}{2}

What is the answer to (x^2-3x-4)/(x+2)=0 ?
The answer to (x^2-3x-4)/(x+2)=0 is x=4,x=-1
Solve for x: (x^2-3x-4)/(x+2)=0
The solution is x=4,x=-1