What is the answer to 2/(1+x^2)=x ?

The answer to 2/(1+x^2)=x is x=1,x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2

Solve for x: 2/(1+x^2)=x

The solution is x=1,x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2

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\frac{2}{1 + x ^{2}} = x

x = 1, x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

Solution steps

\frac{2}{1 + x ^{2}} = x

Multiply both sides by

1 + x^{2}

2 = x (1 + x^{2})

Solve

2 = x (1 + x^{2}) : x = 1, x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

x = 1, x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

\frac{4}{x} - 8 = - 2

y, \frac{x}{y} = h - k

\frac{4}{5 x} = 11

0 = \frac{x + 1}{x + 2}

\frac{2}{t} = \frac{t}{5 t - 12}

What is the answer to 2/(1+x^2)=x ?
The answer to 2/(1+x^2)=x is x=1,x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2
Solve for x: 2/(1+x^2)=x
The solution is x=1,x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2