What is the answer to y= 1/(y^2) ?

The answer to y= 1/(y^2) is y=1,y=-1/2+(sqrt(3))/2 i,y=-1/2-(sqrt(3))/2 i

Solve for y: y= 1/(y^2)

The solution is y=1,y=-1/2+(sqrt(3))/2 i,y=-1/2-(sqrt(3))/2 i

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y = \frac{1}{y ^{2}}

y = 1, y = - \frac{1}{2} + \frac{3}{2} i, y = - \frac{1}{2} - \frac{3}{2} i

Solution steps

y = \frac{1}{y ^{2}}

Multiply both sides by

y^{2}

y^{3} = 1

Solve

y^{3} = 1 : y = 1, y = - \frac{1}{2} + \frac{3}{2} i, y = - \frac{1}{2} - \frac{3}{2} i

y = 1, y = - \frac{1}{2} + \frac{3}{2} i, y = - \frac{1}{2} - \frac{3}{2} i

Verify Solutions

Find undefined (singularity) points:

y = 0

Combine undefined points with solutions:

y = 1, y = - \frac{1}{2} + \frac{3}{2} i, y = - \frac{1}{2} - \frac{3}{2} i

6 \cdot 3 y = \frac{4}{y} - 8

0 = \frac{8}{x}

\frac{2}{x} \cdot + 9 = 5

\frac{144}{y ^{2}} + y^{2} = 40

\frac{4}{5 x} - \frac{1}{3 x} = 5

What is the answer to y= 1/(y^2) ?
The answer to y= 1/(y^2) is y=1,y=-1/2+(sqrt(3))/2 i,y=-1/2-(sqrt(3))/2 i
Solve for y: y= 1/(y^2)
The solution is y=1,y=-1/2+(sqrt(3))/2 i,y=-1/2-(sqrt(3))/2 i