What is the answer to x=(x^3+3x-1)/(x^2) ?

The answer to x=(x^3+3x-1)/(x^2) is x= 1/3

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x=(x^3+3x-1)/(x^2)

x = \frac{x ^{3} + 3 x - 1}{x ^{2}}

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

x = \frac{x ^{3} + 3 x - 1}{x ^{2}}

Multiply both sides by

x^{2}

x^{3} = x^{3} + 3 x - 1

Subtract

x^{3}

from both sides

x^{3} - x^{3} = x^{3} + 3 x - 1 - x^{3}

Simplify

0 = 3 x - 1

Switch sides

3 x - 1 = 0

Move

1

to the right side

3 x = 1

Divide both sides by

3

x = \frac{1}{3}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{1}{3}

8 = \frac{- 18 + ( 3 )}{( 8 ) ( 16 - 40 n )}

x - x^{- 1} = 2

x^{- 2} = 0.01

4 = \frac{1}{3 r - 6}

\frac{x ^{2} - 2 x}{x - 3} = 8

What is the answer to x=(x^3+3x-1)/(x^2) ?
The answer to x=(x^3+3x-1)/(x^2) is x= 1/3
Solve for x: x=(x^3+3x-1)/(x^2)
The solution is x= 1/3