What are the solutions to the equation 10x^2+10x-698=0 ?

The solutions to the equation 10x^2+10x-698=0 are x=(-5+sqrt(7005))/(10),x=-(5+sqrt(7005))/(10)

Find the zeros of 10x^2+10x-698=0

The zeros of 10x^2+10x-698=0 are x=(-5+sqrt(7005))/(10),x=-(5+sqrt(7005))/(10)

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10 x^{2} + 10 x - 698 = 0

x = \frac{- 5 + 7005}{10}, x = - \frac{5 + 7005}{10}

Decimal Notation

x = 7.86958 \dots, x = - 8.86958 \dots

Solution steps

10 x^{2} + 10 x - 698 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 10 ( - 698 )}{2 \cdot 10}

1 0^{2} - 4 \cdot 10 (- 698) = 27005

x_{1, 2} = \frac{- 10 \pm 2 7005}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 10 + 2 7005}{2 \cdot 10}, x_{2} = \frac{- 10 - 2 7005}{2 \cdot 10}

x = \frac{- 10 + 2 7005}{2 \cdot 10} : \frac{- 5 + 7005}{10}

x = \frac{- 10 - 2 7005}{2 \cdot 10} : - \frac{5 + 7005}{10}

The solutions to the quadratic equation are:

x = \frac{- 5 + 7005}{10}, x = - \frac{5 + 7005}{10}

(x - 1) (x + 6) (x - 4) \geq 0

- 10 = - 10 + 7 m

2 (x + 5) = 16

- 2 x + \frac{1}{4} = \frac{1}{4} x + \frac{1}{8}

- 12 x^{3} + 32 x^{4}

What are the solutions to the equation 10x^2+10x-698=0 ?
The solutions to the equation 10x^2+10x-698=0 are x=(-5+sqrt(7005))/(10),x=-(5+sqrt(7005))/(10)
Find the zeros of 10x^2+10x-698=0
The zeros of 10x^2+10x-698=0 are x=(-5+sqrt(7005))/(10),x=-(5+sqrt(7005))/(10)