What is the answer to 4x^{-6}+4x^{-3}-15=0 ?

The answer to 4x^{-6}+4x^{-3}-15=0 is

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4x^{-6}+4x^{-3}-15=0

4 x^{- 6} + 4 x^{- 3} - 15 = 0

Solution steps

4 x^{- 6} + 4 x^{- 3} - 15 = 0

Refine

\frac{4}{x ^{6}} + \frac{4}{x ^{3}} - 15 = 0

Multiply by LCM

4 + 4 x^{3} - 15 x^{6} = 0

Solve

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x + \frac{1}{x} + 4 = 0

\frac{5}{x + 5} = \frac{3}{x + 6}

\frac{1}{1 + 2 ( \frac{x}{4} )} = 0.5

\frac{8 x + 4}{4 - 2 x} = - 6

\frac{1}{x ^{2}} + 2 = \frac{1}{4}

What is the answer to 4x^{-6}+4x^{-3}-15=0 ?
The answer to 4x^{-6}+4x^{-3}-15=0 is
Solve for x: 4x^{-6}+4x^{-3}-15=0
The solution is