What are the solutions to the equation x^2+8x-7=0 ?

The solutions to the equation x^2+8x-7=0 are x=-4+sqrt(23),x=-4-sqrt(23)

Find the zeros of x^2+8x-7=0

The zeros of x^2+8x-7=0 are x=-4+sqrt(23),x=-4-sqrt(23)

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x^{2} + 8 x - 7 = 0

x = - 4 + 23, x = - 4 - 23

Decimal Notation

x = 0.79583 \dots, x = - 8.79583 \dots

Solution steps

x^{2} + 8 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 7) = 223

x_{1, 2} = \frac{- 8 \pm 2 23}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 23}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 23}{2 \cdot 1}

x = \frac{- 8 + 2 23}{2 \cdot 1} : - 4 + 23

x = \frac{- 8 - 2 23}{2 \cdot 1} : - 4 - 23

The solutions to the quadratic equation are:

x = - 4 + 23, x = - 4 - 23

4 x - 3 = 21

2 x + 1 = 7

3 x^{2} = 2 x

1 + 1

∣ x ∣ \geq ∣ 2 x - 1 ∣

What are the solutions to the equation x^2+8x-7=0 ?
The solutions to the equation x^2+8x-7=0 are x=-4+sqrt(23),x=-4-sqrt(23)
Find the zeros of x^2+8x-7=0
The zeros of x^2+8x-7=0 are x=-4+sqrt(23),x=-4-sqrt(23)