What is the answer to t^{-9}-9t^{-3}+8=0 ?

The answer to t^{-9}-9t^{-3}+8=0 is

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t^{-9}-9t^{-3}+8=0

t^{- 9} - 9 t^{- 3} + 8 = 0

Solution steps

t^{- 9} - 9 t^{- 3} + 8 = 0

Refine

\frac{1}{t ^{9}} - \frac{9}{t ^{3}} + 8 = 0

Multiply by LCM

1 - 9 t^{6} + 8 t^{9} = 0

Solve

Verify Solutions

Find undefined (singularity) points:

t = 0

Combine undefined points with solutions:

6 - \frac{1}{x + 1} = \frac{6}{x + 2}

x + 2 + \frac{1}{x} = 0

\frac{1}{x} = \frac{3.55}{1.22}

12.04 = \frac{185}{F e}

p, \frac{1 - p}{p} = x