What is the answer to m^1=-(1/(m^2)) ?

The answer to m^1=-(1/(m^2)) is m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i

Solve for m: m^1=-(1/(m^2))

The solution is m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i

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m^{1} = - (\frac{1}{m ^{2}})

m = - 1, m = \frac{1}{2} - \frac{3}{2} i, m = \frac{1}{2} + \frac{3}{2} i

Solution steps

m^{1} = - (\frac{1}{m ^{2}})

Simplify

- (\frac{1}{m ^{2}}) : - \frac{1}{m ^{2}}

m^{1} = - \frac{1}{m ^{2}}

Multiply both sides by

m^{2}

m^{3} = - 1

Solve

m^{3} = - 1 : m = - 1, m = \frac{1}{2} - \frac{3}{2} i, m = \frac{1}{2} + \frac{3}{2} i

m = - 1, m = \frac{1}{2} - \frac{3}{2} i, m = \frac{1}{2} + \frac{3}{2} i

Verify Solutions

Find undefined (singularity) points:

m = 0

Combine undefined points with solutions:

m = - 1, m = \frac{1}{2} - \frac{3}{2} i, m = \frac{1}{2} + \frac{3}{2} i

3 = \frac{12}{z ^{2}}

\frac{9}{4} = \frac{r}{r - 4}

\frac{23.8}{17} = \frac{53}{x}

\frac{2 x - 3}{x + 1} = 3

\frac{10}{x} = \frac{4}{8}

What is the answer to m^1=-(1/(m^2)) ?
The answer to m^1=-(1/(m^2)) is m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i
Solve for m: m^1=-(1/(m^2))
The solution is m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i