What is the answer to x+x^{-1}=sqrt(2) ?

The answer to x+x^{-1}=sqrt(2) is x=(sqrt(2))/2+i(sqrt(2))/2 ,x=(sqrt(2))/2-i(sqrt(2))/2

Solve for x: x+x^{-1}=sqrt(2)

The solution is x=(sqrt(2))/2+i(sqrt(2))/2 ,x=(sqrt(2))/2-i(sqrt(2))/2

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x + x^{- 1} = 2

x = \frac{2}{2} + i \frac{2}{2}, x = \frac{2}{2} - i \frac{2}{2}

Solution steps

x + x^{- 1} = 2

Refine

x + \frac{1}{x} = 2

Multiply both sides by

x

x^{2} + 1 = 2 x

Solve

x^{2} + 1 = 2 x : x = \frac{2}{2} + i \frac{2}{2}, x = \frac{2}{2} - i \frac{2}{2}

x = \frac{2}{2} + i \frac{2}{2}, x = \frac{2}{2} - i \frac{2}{2}

0 = \frac{x + 13}{x - 11}

(x^{2} + \frac{2}{x})^{12} = x^{9}

y, x = y - \frac{1}{y}

b, - \frac{1}{b} a = c

12 = \frac{2 π}{k}

What is the answer to x+x^{-1}=sqrt(2) ?
The answer to x+x^{-1}=sqrt(2) is x=(sqrt(2))/2+i(sqrt(2))/2 ,x=(sqrt(2))/2-i(sqrt(2))/2
Solve for x: x+x^{-1}=sqrt(2)
The solution is x=(sqrt(2))/2+i(sqrt(2))/2 ,x=(sqrt(2))/2-i(sqrt(2))/2