What is the answer to (64)/x (1+x+x^2)=56 ?

The answer to (64)/x (1+x+x^2)=56 is x=-1/16+i(sqrt(255))/(16),x=-1/16-i(sqrt(255))/(16)

Solve for x: (64)/x (1+x+x^2)=56

The solution is x=-1/16+i(sqrt(255))/(16),x=-1/16-i(sqrt(255))/(16)

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\frac{64}{x} (1 + x + x^{2}) = 56

x = - \frac{1}{16} + i \frac{255}{16}, x = - \frac{1}{16} - i \frac{255}{16}

Solution steps

\frac{64}{x} (1 + x + x^{2}) = 56

Simplify

\frac{64}{x} (1 + x + x^{2}) : \frac{64 ( 1 + x + x ^{2} )}{x}

\frac{64 ( 1 + x + x ^{2} )}{x} = 56

Multiply both sides by

x

64 (1 + x + x^{2}) = 56 x

Solve

64 (1 + x + x^{2}) = 56 x : x = - \frac{1}{16} + i \frac{255}{16}, x = - \frac{1}{16} - i \frac{255}{16}

x = - \frac{1}{16} + i \frac{255}{16}, x = - \frac{1}{16} - i \frac{255}{16}

\frac{5}{2 t - t} = \frac{3 + 3}{2 t}

\frac{1}{x} + x = 3

\frac{10 x - 10}{x - 1} + 12 = x + 8

2 + \frac{7}{a - 7} = \frac{a}{a - 7}

\frac{2}{x} - 4 = - 8 x

What is the answer to (64)/x (1+x+x^2)=56 ?
The answer to (64)/x (1+x+x^2)=56 is x=-1/16+i(sqrt(255))/(16),x=-1/16-i(sqrt(255))/(16)
Solve for x: (64)/x (1+x+x^2)=56
The solution is x=-1/16+i(sqrt(255))/(16),x=-1/16-i(sqrt(255))/(16)