What is the answer to solvefor x,z=(x+y)/(mx) ?

The answer to solvefor x,z=(x+y)/(mx) is x= y/(mz-1);\quad m\ne 0,m\ne 1/z

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solvefor x,z=(x+y)/(mx)

solve for

x, z = \frac{x + y}{m x}

x = \frac{y}{m z - 1}; m \neq = 0, m \neq = \frac{1}{z}

Solution steps

z = \frac{x + y}{m x}

Multiply both sides by

x

z x = \frac{x + y}{m}

Multiply both sides by

m

z x m = x + y; m \neq = 0

Move

x

to the left side

z x m - x = y; m \neq = 0

Factor

z x m - x : x (m z - 1)

x (m z - 1) = y; m \neq = 0

Divide both sides by

m z - 1; m \neq = 0, m \neq = \frac{1}{z}

x = \frac{y}{m z - 1}; m \neq = 0, m \neq = \frac{1}{z}

\frac{x}{x - 6} + 3 = \frac{6}{x - 6}

x^{2} - 1 = \frac{1}{x}

8 = \frac{10}{r} \cdot r^{2}

\frac{34 + 3 x}{18 + x} = 2.2

5 + \frac{z}{z + 2} = 1

What is the answer to solvefor x,z=(x+y)/(mx) ?
The answer to solvefor x,z=(x+y)/(mx) is x= y/(mz-1);\quad m\ne 0,m\ne 1/z