What are the solutions to the equation 3x^2+9x=0 ?

The solutions to the equation 3x^2+9x=0 are x=0,x=-3

Find the zeros of 3x^2+9x=0

The zeros of 3x^2+9x=0 are x=0,x=-3

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3 x^{2} + 9 x = 0

x = 0, x = - 3

Solution steps

3 x^{2} + 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

9^{2} - 4 \cdot 3 \cdot 0 = 9

x_{1, 2} = \frac{- 9 \pm 9}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 9 + 9}{2 \cdot 3}, x_{2} = \frac{- 9 - 9}{2 \cdot 3}

x = \frac{- 9 + 9}{2 \cdot 3} : 0

x = \frac{- 9 - 9}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = 0, x = - 3

2 k^{2} + 13 k + 18

x^{2} + 4 = 8

12 a^{5} b^{2} - 36 a^{4} b^{3} - 6 a^{2} b^{2}

y^{2} - y

\frac{2}{3} = \frac{z}{15}

What are the solutions to the equation 3x^2+9x=0 ?
The solutions to the equation 3x^2+9x=0 are x=0,x=-3
Find the zeros of 3x^2+9x=0
The zeros of 3x^2+9x=0 are x=0,x=-3