What is the answer to solvefor a, b/a =c+3b ?

The answer to solvefor a, b/a =c+3b is a= b/(c+3b);\quad b\ne-c/3

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solvefor a, b/a =c+3b

solve for

a, \frac{b}{a} = c + 3 b

a = \frac{b}{c + 3 b}; b \neq = - \frac{c}{3}

Solution steps

\frac{b}{a} = c + 3 b

Multiply both sides by

a

b = c a + 3 ba

Switch sides

c a + 3 ba = b

Factor

c a + 3 ba : a (c + 3 b)

a (c + 3 b) = b

Divide both sides by

c + 3 b; b \neq = - \frac{c}{3}

a = \frac{b}{c + 3 b}; b \neq = - \frac{c}{3}

2 = \frac{x + 7}{x - 9}

x^{2} = \frac{1}{x + 3}

x + \frac{1}{x} = 143

\frac{96}{v} = 6

\frac{6}{x} + \frac{2 x}{3} = 5

What is the answer to solvefor a, b/a =c+3b ?
The answer to solvefor a, b/a =c+3b is a= b/(c+3b);\quad b\ne-c/3